\(\int \frac {x^9}{(1-x^4)^{3/2}} \, dx\) [899]

Optimal result

Integrand size = 15, antiderivative size = 45 \[ \int \frac {x^9}{\left (1-x^4\right )^{3/2}} \, dx=\frac {x^6}{2 \sqrt {1-x^4}}+\frac {3}{4} x^2 \sqrt {1-x^4}-\frac {3 \arcsin \left (x^2\right )}{4} \]

[Out]

-3/4*arcsin(x^2)+1/2*x^6/(-x^4+1)^(1/2)+3/4*x^2*(-x^4+1)^(1/2)

Rubi [A] (verified)

Time = 0.01 (sec) , antiderivative size = 45, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.267, Rules used = {281, 294, 327, 222} \[ \int \frac {x^9}{\left (1-x^4\right )^{3/2}} \, dx=-\frac {3 \arcsin \left (x^2\right )}{4}+\frac {x^6}{2 \sqrt {1-x^4}}+\frac {3}{4} \sqrt {1-x^4} x^2 \]

[In]

Int[x^9/(1 - x^4)^(3/2),x]

[Out]

x^6/(2*Sqrt[1 - x^4]) + (3*x^2*Sqrt[1 - x^4])/4 - (3*ArcSin[x^2])/4

Rule 222

Int[1/Sqrt[(a_) + (b_.)*(x_)^2], x_Symbol] :> Simp[ArcSin[Rt[-b, 2]*(x/Sqrt[a])]/Rt[-b, 2], x] /; FreeQ[{a, b}
, x] && GtQ[a, 0] && NegQ[b]

Rule 281

Int[(x_)^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> With[{k = GCD[m + 1, n]}, Dist[1/k, Subst[Int[x^((m
+ 1)/k - 1)*(a + b*x^(n/k))^p, x], x, x^k], x] /; k != 1] /; FreeQ[{a, b, p}, x] && IGtQ[n, 0] && IntegerQ[m]

Rule 294

Int[((c_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[c^(n - 1)*(c*x)^(m - n + 1)*((a + b*x^
n)^(p + 1)/(b*n*(p + 1))), x] - Dist[c^n*((m - n + 1)/(b*n*(p + 1))), Int[(c*x)^(m - n)*(a + b*x^n)^(p + 1), x
], x] /; FreeQ[{a, b, c}, x] && IGtQ[n, 0] && LtQ[p, -1] && GtQ[m + 1, n] &&  !ILtQ[(m + n*(p + 1) + 1)/n, 0]
&& IntBinomialQ[a, b, c, n, m, p, x]

Rule 327

Int[((c_.)*(x_))^(m_)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[c^(n - 1)*(c*x)^(m - n + 1)*((a + b*x^n
)^(p + 1)/(b*(m + n*p + 1))), x] - Dist[a*c^n*((m - n + 1)/(b*(m + n*p + 1))), Int[(c*x)^(m - n)*(a + b*x^n)^p
, x], x] /; FreeQ[{a, b, c, p}, x] && IGtQ[n, 0] && GtQ[m, n - 1] && NeQ[m + n*p + 1, 0] && IntBinomialQ[a, b,
c, n, m, p, x]

Rubi steps \begin{align*} \text {integral}& = \frac {1}{2} \text {Subst}\left (\int \frac {x^4}{\left (1-x^2\right )^{3/2}} \, dx,x,x^2\right ) \\ & = \frac {x^6}{2 \sqrt {1-x^4}}-\frac {3}{2} \text {Subst}\left (\int \frac {x^2}{\sqrt {1-x^2}} \, dx,x,x^2\right ) \\ & = \frac {x^6}{2 \sqrt {1-x^4}}+\frac {3}{4} x^2 \sqrt {1-x^4}-\frac {3}{4} \text {Subst}\left (\int \frac {1}{\sqrt {1-x^2}} \, dx,x,x^2\right ) \\ & = \frac {x^6}{2 \sqrt {1-x^4}}+\frac {3}{4} x^2 \sqrt {1-x^4}-\frac {3}{4} \sin ^{-1}\left (x^2\right ) \\ \end{align*}

Mathematica [A] (verified)

Time = 0.21 (sec) , antiderivative size = 32, normalized size of antiderivative = 0.71 \[ \int \frac {x^9}{\left (1-x^4\right )^{3/2}} \, dx=\frac {1}{4} \left (-\frac {x^2 \left (-3+x^4\right )}{\sqrt {1-x^4}}-3 \arcsin \left (x^2\right )\right ) \]

[In]

Integrate[x^9/(1 - x^4)^(3/2),x]

[Out]

(-((x^2*(-3 + x^4))/Sqrt[1 - x^4]) - 3*ArcSin[x^2])/4

Maple [A] (verified)

Time = 4.14 (sec) , antiderivative size = 27, normalized size of antiderivative = 0.60

method	result	size
risch	\(-\frac {x^{2} \left (x^{4}-3\right )}{4 \sqrt {-x^{4}+1}}-\frac {3 \arcsin \left (x^{2}\right )}{4}\)	\(27\)
pseudoelliptic	\(-\frac {x^{6}+3 \arcsin \left (x^{2}\right ) \sqrt {-x^{4}+1}-3 x^{2}}{4 \sqrt {-x^{4}+1}}\)	\(36\)
meijerg	\(-\frac {i \left (\frac {i \sqrt {\pi }\, x^{2} \left (-5 x^{4}+15\right )}{10 \sqrt {-x^{4}+1}}-\frac {3 i \sqrt {\pi }\, \arcsin \left (x^{2}\right )}{2}\right )}{2 \sqrt {\pi }}\)	\(43\)
trager	\(\frac {x^{2} \left (x^{4}-3\right ) \sqrt {-x^{4}+1}}{4 x^{4}-4}+\frac {3 \operatorname {RootOf}\left (\textit {\_Z}^{2}+1\right ) \ln \left (-\operatorname {RootOf}\left (\textit {\_Z}^{2}+1\right ) \sqrt {-x^{4}+1}+x^{2}\right )}{4}\)	\(58\)
default	\(-\frac {3 \arcsin \left (x^{2}\right )}{4}+\frac {x^{2} \sqrt {-x^{4}+1}}{4}-\frac {\sqrt {-\left (x^{2}-1\right )^{2}+2-2 x^{2}}}{4 \left (x^{2}-1\right )}-\frac {\sqrt {-\left (x^{2}+1\right )^{2}+2+2 x^{2}}}{4 \left (x^{2}+1\right )}\)	\(76\)
elliptic	\(-\frac {3 \arcsin \left (x^{2}\right )}{4}+\frac {x^{2} \sqrt {-x^{4}+1}}{4}-\frac {\sqrt {-\left (x^{2}-1\right )^{2}+2-2 x^{2}}}{4 \left (x^{2}-1\right )}-\frac {\sqrt {-\left (x^{2}+1\right )^{2}+2+2 x^{2}}}{4 \left (x^{2}+1\right )}\)	\(76\)

[In]

int(x^9/(-x^4+1)^(3/2),x,method=_RETURNVERBOSE)

[Out]

-1/4*x^2*(x^4-3)/(-x^4+1)^(1/2)-3/4*arcsin(x^2)

Fricas [A] (verification not implemented)

none

Time = 0.27 (sec) , antiderivative size = 52, normalized size of antiderivative = 1.16 \[ \int \frac {x^9}{\left (1-x^4\right )^{3/2}} \, dx=\frac {6 \, {\left (x^{4} - 1\right )} \arctan \left (\frac {\sqrt {-x^{4} + 1} - 1}{x^{2}}\right ) + {\left (x^{6} - 3 \, x^{2}\right )} \sqrt {-x^{4} + 1}}{4 \, {\left (x^{4} - 1\right )}} \]

[In]

integrate(x^9/(-x^4+1)^(3/2),x, algorithm="fricas")

[Out]

1/4*(6*(x^4 - 1)*arctan((sqrt(-x^4 + 1) - 1)/x^2) + (x^6 - 3*x^2)*sqrt(-x^4 + 1))/(x^4 - 1)

Sympy [C] (verification not implemented)

Result contains complex when optimal does not.

Time = 1.55 (sec) , antiderivative size = 82, normalized size of antiderivative = 1.82 \[ \int \frac {x^9}{\left (1-x^4\right )^{3/2}} \, dx=\begin {cases} \frac {i x^{6}}{4 \sqrt {x^{4} - 1}} - \frac {3 i x^{2}}{4 \sqrt {x^{4} - 1}} + \frac {3 i \operatorname {acosh}{\left (x^{2} \right )}}{4} & \text {for}\: \left |{x^{4}}\right | > 1 \\- \frac {x^{6}}{4 \sqrt {1 - x^{4}}} + \frac {3 x^{2}}{4 \sqrt {1 - x^{4}}} - \frac {3 \operatorname {asin}{\left (x^{2} \right )}}{4} & \text {otherwise} \end {cases} \]

[In]

integrate(x**9/(-x**4+1)**(3/2),x)

[Out]

Piecewise((I*x**6/(4*sqrt(x**4 - 1)) - 3*I*x**2/(4*sqrt(x**4 - 1)) + 3*I*acosh(x**2)/4, Abs(x**4) > 1), (-x**6
/(4*sqrt(1 - x**4)) + 3*x**2/(4*sqrt(1 - x**4)) - 3*asin(x**2)/4, True))

Maxima [A] (verification not implemented)

none

Time = 0.29 (sec) , antiderivative size = 60, normalized size of antiderivative = 1.33 \[ \int \frac {x^9}{\left (1-x^4\right )^{3/2}} \, dx=-\frac {\frac {3 \, {\left (x^{4} - 1\right )}}{x^{4}} - 2}{4 \, {\left (\frac {\sqrt {-x^{4} + 1}}{x^{2}} + \frac {{\left (-x^{4} + 1\right )}^{\frac {3}{2}}}{x^{6}}\right )}} + \frac {3}{4} \, \arctan \left (\frac {\sqrt {-x^{4} + 1}}{x^{2}}\right ) \]

[In]

integrate(x^9/(-x^4+1)^(3/2),x, algorithm="maxima")

[Out]

-1/4*(3*(x^4 - 1)/x^4 - 2)/(sqrt(-x^4 + 1)/x^2 + (-x^4 + 1)^(3/2)/x^6) + 3/4*arctan(sqrt(-x^4 + 1)/x^2)

Giac [A] (verification not implemented)

none

Time = 0.38 (sec) , antiderivative size = 33, normalized size of antiderivative = 0.73 \[ \int \frac {x^9}{\left (1-x^4\right )^{3/2}} \, dx=\frac {{\left (x^{4} - 3\right )} \sqrt {-x^{4} + 1} x^{2}}{4 \, {\left (x^{4} - 1\right )}} - \frac {3}{4} \, \arcsin \left (x^{2}\right ) \]

[In]

integrate(x^9/(-x^4+1)^(3/2),x, algorithm="giac")

[Out]

1/4*(x^4 - 3)*sqrt(-x^4 + 1)*x^2/(x^4 - 1) - 3/4*arcsin(x^2)

Mupad [F(-1)]

Timed out. \[ \int \frac {x^9}{\left (1-x^4\right )^{3/2}} \, dx=\int \frac {x^9}{{\left (1-x^4\right )}^{3/2}} \,d x \]

[In]

int(x^9/(1 - x^4)^(3/2),x)

[Out]

int(x^9/(1 - x^4)^(3/2), x)